Independent and Dependent Events - By Anywhere Math
Transcript
00:0-1 | Okay . I got my good friend , cal here | |
00:01 | to help us out . We got two jokers cal | |
00:04 | go ahead , take those . We've got a full | |
00:05 | deck of cards , Right , They're all different . | |
00:08 | Nothing special . So first he's gonna put in one | |
00:11 | of those jokers anywhere you want . Go for it | |
00:14 | . Next one . Just tell me when to stop | |
00:16 | and we'll put the other one . Okay ? Put | |
00:19 | both of them in there , just there . Random | |
00:21 | . Right ? And we think what's the probability of | |
00:24 | cow randomly choosing one of those jokers ? What do | |
00:27 | you think The probability of that is almost impossible . | |
00:29 | Almost impossible . I would agree . Right , so | |
00:31 | cal you go ahead , tell me when to start | |
00:34 | . Let's see . Oh the joker . Oh my | |
00:38 | God , got it . Let's do it again . | |
00:40 | What would be the probability if he will mix these | |
00:43 | up again ? Put it anywhere . Are you Sorry | |
00:47 | , go ahead and tell me again when to stop | |
00:49 | . Stop . Okay , put it in there again | |
00:52 | . What would be the probability of him choosing the | |
00:54 | card again ? What do you think ? So , | |
00:57 | getting a joker and a joker a second time . | |
01:00 | What do you think ? The probability ? How many | |
01:02 | cars ? So now we've got 54 total 54 than | |
01:06 | one 50 . Okay , but there's actually two jokers | |
01:11 | still two out of 54 . So let's see if | |
01:15 | he can randomly choose it again . Ready ? Tell | |
01:16 | me when to stop . Stop there . All right | |
01:20 | . Oh my God , it again . So welcome | |
01:23 | to anywhere . Math . I'm Jeff , Jacobson , | |
01:25 | this is cow . Today we're gonna talk about independent | |
01:28 | and dependent events . Let's get started . All right | |
01:49 | , So today we're talking about independent versus dependent events | |
01:53 | . So , first , let's talk about what exactly | |
01:55 | those are . We're talking about compound events . These | |
01:58 | are two types of compound events . So first , | |
02:01 | independent events are when one event does not affect the | |
02:06 | likelihood the next event will occur . So let's kind | |
02:10 | of talk about that in plain english , let's say | |
02:13 | are two events were flipping a coin and rolling a | |
02:15 | die . Now , if I flip heads , does | |
02:19 | that change the probability of me rolling a five ? | |
02:23 | No , right . This dye does not care what | |
02:27 | I flip here . These are completely separate . They | |
02:30 | are independent of one another . If I flip my | |
02:34 | head's , it doesn't mean I'm gonna roll a six | |
02:37 | , right ? The probability of me rolling a six | |
02:40 | is still one out of six , no matter what | |
02:42 | happens here , dependent events . One event does affect | |
02:47 | the likelihood of the next event occurring . So the | |
02:51 | probability of the next event depends on what happens . | |
02:55 | First . Let's look at an example . All right | |
02:58 | . Example , one find the probability of rolling a | |
03:00 | prime number and flipping heads . So we're talking about | |
03:04 | rolling a die and flipping heads on a coin . | |
03:07 | Um Now if you think again , we're talking about | |
03:10 | independent or dependent events , what would this compound event | |
03:14 | be ? Independent ? Independent And hopefully you realize it's | |
03:17 | independent . Like we said , these don't care what | |
03:20 | what the other did their independent of each other . | |
03:22 | So it's an independent event . Now for an independent | |
03:28 | event , independent events . There's a formula we can | |
03:34 | use for finding the probability . Now you may have | |
03:37 | done before tree diagrams or tables to find all the | |
03:41 | possible outcomes and and then you can find the probability | |
03:43 | that way , but that can take a lot of | |
03:46 | time . So instead we have a formula where the | |
03:48 | probability of A and be that's equal to well , | |
03:54 | just the individual probabilities multiplied by each other . So | |
03:58 | probability of a times probability of B . Well let's | |
04:04 | do that . So we're finding the probability of prime | |
04:08 | number . Mhm . And heads mike . And just | |
04:16 | abbreviate probability of prime and Heads is going to be | |
04:20 | equal to the probability of what was a what's that | |
04:24 | first event ? A prime number ? What's the probability | |
04:27 | of getting a prime number times ? The probability of | |
04:32 | flipping hands ? Mhm . Okay . So first , | |
04:37 | what is the probability of getting a prime number when | |
04:40 | you roll it die ? Well , one is not | |
04:43 | prime two is Prime . 3's prime four . No | |
04:48 | , that's composite . five . That is prime and | |
04:50 | six is composite . So three Out of those six | |
04:55 | numbers are prime . Right ? 2 , 3 and | |
04:59 | five . What is the probability of getting a heads | |
05:02 | ? Well , one out of two . Right , | |
05:04 | we know that . So 36 times . One half | |
05:07 | . Well , I can make that simplified one half | |
05:09 | and I get 14 Here's one to try on your | |
05:14 | own . Okay . Example to find the probability of | |
05:22 | choosing both jokers . Now this is similar to what | |
05:25 | we did with cow earlier except with cow when he | |
05:29 | chose a joker , we put it back in the | |
05:32 | deck . This time when we choose a joker , | |
05:35 | we're leaving it out . First . Is this independent | |
05:39 | or dependent ? If you choose something and put it | |
05:41 | back ? Well then it doesn't affect the next time | |
05:44 | . But if you choose something and leave it out | |
05:47 | , it does . So you gotta be careful with | |
05:49 | that . So this is a dependent event . Let's | |
05:53 | go over . 1st . The formula for a dependent | |
05:57 | event , probability of A . And B is going | |
06:03 | to be equal to the probability of a . Whatever | |
06:06 | is happening . First times the probability of B . | |
06:10 | Now this is where it's a little different . The | |
06:12 | probability of getting be after hey , after a has | |
06:20 | already happened . Well . First probability of A and | |
06:22 | B . Well , I'm doing probability of in this | |
06:25 | case a joker and another joker right ? We want | |
06:31 | both jokers . The probability of joking and jokers so | |
06:33 | that the probability of getting a joker times probability of | |
06:39 | and this is getting repetitive joker after a joker has | |
06:45 | already been chosen . Yeah . again , there's 52 | |
06:49 | normal cards in a deck . There are two jokers | |
06:54 | . So all together there are 54 cards . So | |
06:59 | the probability of choosing a joker the first time is | |
07:02 | two , there's two ways to get it out of | |
07:06 | 54 total cards . Okay , now what's the probability | |
07:13 | of getting a joker after a joker has already been | |
07:16 | chosen ? Well , imagine that . So if we | |
07:19 | already chose that joker , now there's only one joker | |
07:23 | left . one way to get a joker And right | |
07:27 | , we took a card away . So now there's | |
07:29 | only 53 , 53 cards total . So that's the | |
07:35 | probability of getting the next Joker . Only one out | |
07:38 | of 53 . Because we assume we already chose one | |
07:41 | . Okay , so now we can finish doing this | |
07:46 | so I can simplify . That becomes one and 27 | |
07:49 | 1 times one is 1 27 times 51 out of | |
07:56 | 101,431 . So the probability of getting two jokers without | |
08:04 | replacing , which is what we just talked about one | |
08:07 | in 1431 . Very very difficult . But if you're | |
08:12 | wondering what cow did earlier , right . Is he | |
08:15 | just very , very lucky . Well , probability of | |
08:17 | getting those two jokers right ? A joker and then | |
08:20 | another joker With replacement . Remember we put it back | |
08:23 | in ? Well that's two out of 54 for that | |
08:26 | first Joker , there's two jokers . 54 total . | |
08:29 | The next Joker . It's still the same because we | |
08:32 | replaced it . That could simplify to one and 27 | |
08:36 | same thing here . One in 27 , which equals | |
08:39 | one in 729 . So obviously cow is very , | |
08:47 | very lucky . Okay , here's the last example example | |
08:56 | three . Find the probability of choosing a heart , | |
09:00 | putting it back and then choosing a spade . So | |
09:03 | here are my cards , right ? If you count | |
09:06 | them all up , You should notice there are eight | |
09:10 | . Now we gotta think first , is this going | |
09:13 | to be dependent or independent ? The key phrase here | |
09:17 | is that we put it back after we do the | |
09:20 | first after we choose the first card . So that | |
09:24 | should tell you things aren't changing . It's going to | |
09:27 | be independent . The probability of choosing a heart , | |
09:32 | Putting it back and then choosing a spade . So | |
09:38 | heart and spade . That's just gonna be probability of | |
09:42 | the heart times probability of the spade . Well , | |
09:46 | what's the probability of choosing a heart ? Well , | |
09:48 | how many hearts are there ? There are one too | |
09:52 | . Right . The probability of the heart is two | |
09:55 | out of a total times probability of a space . | |
10:01 | So remember if we choose a heart but we put | |
10:04 | it back so things are changing . There's still eight | |
10:08 | total . And how many spades are there ? Well | |
10:12 | , if you remember these , this is a spade | |
10:14 | here . That queen . And let's see there's two | |
10:19 | more spades right there . I think that's all of | |
10:22 | them . That's a club . So three out of | |
10:25 | it . Okay , We can simplify 1 4th And | |
10:32 | that equals three out of 32 . Okay , here's | |
10:35 | one more to try on your own as always . | |
10:42 | Thank you so much for watching . And if you | |
10:43 | like this video , please subscribe . Yeah . |
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