Simultaneous Equations - Example to solve 1 - By tecmath
Transcript
| 00:00 | Good day and welcome to the Tech Math channel . | |
| 00:02 | What are we looking at in this video is how | |
| 00:04 | to solve simultaneous equations . So basically when you go | |
| 00:07 | through a whole bunch of examples of these uh , | |
| 00:10 | different videos , what I'm also going to put up | |
| 00:12 | the end of each video is a link eventually to | |
| 00:15 | away . Once you get used to these of solving | |
| 00:17 | these a little bit differently , you might find it | |
| 00:20 | a little bit easier , but I think it's really | |
| 00:21 | worth getting This method worked out 1st . So the | |
| 00:26 | way we solve these first off simultaneous equations is where | |
| 00:29 | we have to algebraic equations . Okay , these equations | |
| 00:32 | that have these exes and wise these variables in them | |
| 00:35 | and we use these two equations to solve these unknown | |
| 00:39 | variables . Okay , um the way that we do | |
| 00:42 | this is we have to get at least one set | |
| 00:45 | of these coefficients , the numbers in front of these | |
| 00:47 | variables . The same Okay . As you see at | |
| 00:49 | the moment , this is the same as one why | |
| 00:52 | ? And this is to why ? This is four | |
| 00:53 | excesses three X . So that none of them match | |
| 00:56 | up . Okay , There's the wires are different . | |
| 00:58 | The exes are different . So we have to make | |
| 01:00 | at least one set of them the same . The | |
| 01:03 | easiest way to do that is we get equation one | |
| 01:05 | here and we times it by two . And this | |
| 01:09 | is the result . I want to put equation one | |
| 01:12 | here equation to there . Now we multiply equation one | |
| 01:16 | x 2 , we get Idec's plus two , why | |
| 01:21 | equals 14 and equation to stays the same three X | |
| 01:29 | plus two Y vehicles died . Then what we can | |
| 01:33 | do is we can take Equation one of the equations | |
| 01:37 | from the other and you can see this and we | |
| 01:39 | can go ahead X . Take away three X . | |
| 01:42 | And it gives us five X . To why take | |
| 01:46 | away to why these guys cancel each other out . | |
| 01:49 | And 14 take away nine gives us five . So | |
| 01:53 | five X equals five . That means X equals one | |
| 01:58 | . Now to work out why what we do is | |
| 01:59 | we substitute X into the equations here . So I'll | |
| 02:03 | do it for both equations up here four times one | |
| 02:08 | Is four . So 4 Times one equals 4 plus | |
| 02:13 | why equal seven ? So four plus Y . Eagle | |
| 02:19 | seven . That means why is equal to three . | |
| 02:23 | And that's for equation one . I'll tell you what | |
| 02:26 | I do . Also substitute it into equation too . | |
| 02:29 | So same sort of thing three times X . So | |
| 02:34 | three axes three times X . is three plus two | |
| 02:38 | Y . Well I'll call you why three So two | |
| 02:40 | times three is six and this equals nine . So | |
| 02:46 | indeed that is correct . It means our answer is | |
| 02:48 | correct . So I'm going to put a link up | |
| 02:50 | for the next video but also for a way that | |
| 02:53 | you might find these different way of solving these . | |
| 02:56 | Okay . But I think it's really worth getting these | |
| 02:58 | nails on how to work this out properly anyway . | |
| 03:01 | I hope to see the next video . Bye . |
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