Can you solve this tricky math problem? - By tecmath
Transcript
| 00:0-1 | Welcome to the Tech mouth channel . I'm josh . | |
| 00:02 | Fireback . Consider this diagram here We're going to be | |
| 00:05 | looking for four unknown numbers that can be used to | |
| 00:07 | make these equations correct ? That is to say this | |
| 00:10 | number plus this number will be equal to eight . | |
| 00:13 | This number subtract this number will be equal six . | |
| 00:16 | This number plus this number will equal 13 . And | |
| 00:19 | this number plus this number will be equal to eight | |
| 00:22 | . Suppose this video . If you'd like to give | |
| 00:24 | this problem and try and when you're ready to keep | |
| 00:26 | watching and learn how to solve this problem , start | |
| 00:28 | up again . Yeah . Yeah . Mhm . So | |
| 00:39 | how can we solve this problem ? First off , | |
| 00:41 | let's label these four unknown numbers to help us out | |
| 00:44 | . We'll call this one A . This one be | |
| 00:46 | this one C . And this one D . Now | |
| 00:49 | we know a couple of things here . We know | |
| 00:52 | that C plus A . Is equal to 13 . | |
| 00:56 | We also know that B plus a is equal to | |
| 01:00 | eight . So we can use elimination to form a | |
| 01:03 | new equation where they will counselor . A . A | |
| 01:07 | subtract A . C . Will subtract B . And | |
| 01:10 | here we'll have 13 subtract leaving us with five . | |
| 01:14 | So we have a new equation relating to see and | |
| 01:17 | be . We also know that be Plus D . | |
| 01:22 | is equal to eight . We know that C . | |
| 01:25 | Subtract D is equal to six . So once again | |
| 01:29 | we can use elimination to form a new equation positive | |
| 01:33 | D . A . Negative D . Will cancel each | |
| 01:35 | other out . What we'll do here is we will | |
| 01:37 | end up with C plus B . And on this | |
| 01:40 | side we'll have the product of eight and six which | |
| 01:43 | is equal to 14 . Now we have two brand | |
| 01:46 | new equations relating to see and be . We can | |
| 01:50 | use once again simultaneous equations to solve these . So | |
| 01:54 | as you can see negative be a positive be cancel | |
| 01:57 | each other out when we put these two equations together | |
| 02:00 | , C plus C is equal to to see This | |
| 02:04 | is equal to 14-plus 5 which is equal to 19 | |
| 02:08 | . Therefore , what do we have ? Well , | |
| 02:10 | it to C is equal to 19 , C is | |
| 02:12 | equal to half of that , which is 9.5 . | |
| 02:16 | So we can go through now and start substituting in | |
| 02:19 | some values . We know that . See here is | |
| 02:21 | equal to 9.5 . What else do we have ? | |
| 02:25 | 9.5 . Take away one Ankle 6 . This will | |
| 02:28 | be 3.5 . The product of this number 9.5 plus | |
| 02:33 | . This unknown number is 13 . So therefore this | |
| 02:36 | number up the top here has to be 3.5 . | |
| 02:39 | The product of 3.5 plus is unknown number is eight | |
| 02:42 | . Therefore this unknown number has to be 4.5 , | |
| 02:46 | 4.5 and 3.5 do add up to Eagle eight , | |
| 02:49 | so we know that our answer is correct , and | |
| 02:51 | that's the answer . Thanks for watching the Tech Math | |
| 02:54 | channel . As always , a big thank you to | |
| 02:56 | my subscribers and patrons for your support . Please comment | |
| 02:59 | below and email me with any math problems or videos | |
| 03:01 | you would live made . See you next time . |
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