GRE Math Test Prep | MathHelp.com - By MathHelp.com
Transcript
| 00:0-1 | to simplify the square root of 500 X . To | |
| 00:03 | the fourth . Why to the third ? We start | |
| 00:07 | by making a factor tree for 500 . 500 is | |
| 00:12 | five times 100 . And you should be able to | |
| 00:17 | recognize 100 as a perfect square . 10 times 10 | |
| 00:25 | . So to start with we have a pair of | |
| 00:27 | 10s . Think of X to the fourth as X | |
| 00:34 | times X times X times X . So we have | |
| 00:39 | two pairs of access . And think of why to | |
| 00:44 | the 3rd as Why Times Why Times Why ? So | |
| 00:50 | we have one pair of wise so attend an ex | |
| 00:56 | . Another X . And a Y . Can all | |
| 00:59 | come out of the radical . And we have 10 | |
| 01:05 | X squared . Why ? On the outside notice that | |
| 01:10 | everything that comes out multiplies together What we're left with | |
| 01:16 | on the inside are the five and the why that | |
| 01:19 | don't pair up . So we have square root of | |
| 01:23 | five Y . And the answer is 10 X squared | |
| 01:28 | Y . Times the square root of five Y . |
Summarizer
DESCRIPTION:
This lesson covers the product rule. Students learn the product rule, which states that when multiplying two powers that have the same base, add the exponents. For example, x^4 times x^3 = x^7. To multiply 6s^3 times 3s^6, multiply the coefficients and add the exponents, to get 18s^9. If there is no exponent on the variable, it can be given an exponent of 1. For example, x can be thought of as x^1.
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