Intermediate Algebra | MathHelp.com - Free Educational videos for Students in K-12 | Lumos Learning

Intermediate Algebra | MathHelp.com - Free Educational videos for Students in k-12


Intermediate Algebra | MathHelp.com - By MathHelp.com



Transcript
00:0-1 don't be intimidated by the fraction that appears on the
00:03 left side of this equation . We start this problem
00:06 the same way by distributing through the parentheses on both
00:10 sides . So as we distribute this 1/5 through the
00:15 parentheses on the left side of the equation , we
00:18 get 1/5 times Y . Which is why over five
00:23 and 1/5 times negative one , which is negative 1/5
00:29 On the right . Let's change this -2 to plus
00:33 a negative too , so that we know we're distributing
00:37 a negative too through the parentheses . When we do
00:41 that , the right side of the equation simplifies to
00:45 6 -8 plus two Y . And notice that we
00:51 can go one step further with the right side of
00:53 the equation as it simplifies to negative two plus two
00:59 Y . Bring down the Y over five minus 1/5
01:07 and you're ready to get rid of the fractions .
01:10 Since both fractions have a denominator of five , we
01:14 can get rid of the fractions by multiplying both sides
01:17 of the equation by five . Mhm . Oh ,
01:26 make sure you distribute the five through both terms on
01:32 both sides of the equation On the left are fives
01:37 cancel , and we're left with Y -1 on the
01:44 right , five times negative two is negative 10 And
01:49 five times positive two y is positive 10 y .
01:55 From here , you should be able to easily finish
01:58 the problem .
Summarizer

DESCRIPTION:

This lesson covers motion problems. Students learn to solve advanced "motion" word problems -- for example, riding a bike to pick up a car and driving back, or biking part of a trip and taking a boat the rest of the trip. Students should first draw a diagram to represent the relationship between the distances involved in the problem, then set up a chart based on the formula rate times time = distance. The chart is then used to set up the equation.

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