Math Antics - Mean, Median and Mode - By Mathantics
Transcript
00:03 | Uh huh . Hi , this is rob . Welcome | |
00:07 | to Math Antics . In this lesson we're going to | |
00:09 | learn about three important math concepts called the mean the | |
00:12 | median and the mode math often deals with datasets and | |
00:16 | data sets are often just collections or groups of numbers | |
00:20 | . These numbers may be the results of scientific measurements | |
00:23 | or surveys or other data collection methods . For example | |
00:27 | , you might record the ages of each member of | |
00:29 | your family into a data set or you might measure | |
00:32 | the weight of each of your pets unless them in | |
00:34 | a dataset . Those data sets are fairly small and | |
00:37 | easy to understand . But you could have much bigger | |
00:40 | datasets . A really big data set might contain the | |
00:42 | cost of every item in a store or the top | |
00:45 | speed of every land mammal or the brightness of all | |
00:48 | the stars in our galaxy . Those data sets will | |
00:51 | contain a lot of different numbers . And if you | |
00:54 | have to look at a big data set all at | |
00:55 | one time it would be pretty hard to make sense | |
00:58 | of it or say much about it besides , well | |
01:00 | that's a lot of numbers but that's where mean , | |
01:03 | median and mode can really help us out . There | |
01:06 | are three different properties a data sets that can give | |
01:09 | us useful . Easy to understand information about the data | |
01:11 | set so that we can see the big picture and | |
01:14 | understand what the data means about the world we live | |
01:16 | in . That sounds pretty useful . Huh ? So | |
01:19 | let's learn what each property really is and find out | |
01:21 | how to calculate them for any particular dataset . Let's | |
01:25 | start with the mean . You may not have ever | |
01:27 | heard of something called the mean before but I'll bet | |
01:30 | you've heard of the average . If so then I've | |
01:33 | got good news . Mean means average mean an average | |
01:37 | are just two different terms for the exact same property | |
01:39 | of a data set . The mean or average is | |
01:42 | an extremely useful property to understand what it is . | |
01:45 | Let's look at a simple data set that contains five | |
01:47 | numbers as a visual aid . Let's also represent those | |
01:50 | numbers with stacks of blocks whose heights correspond to their | |
01:53 | values 183 to 6 . Right now , since each | |
01:58 | of the five numbers is different , the stacks of | |
02:01 | blocks are all different heights . But what if we | |
02:03 | rearrange the blocks with the goal of making the stacks | |
02:06 | of the same height ? In other words , if | |
02:08 | each stack could have the exact same amount , what | |
02:10 | would that amount be ? Well with a bit of | |
02:13 | trial and error ? You'll see that we have enough | |
02:14 | blocks for each stack to have a total of four | |
02:17 | . That means that the mean or average for original | |
02:20 | Dataset would be four . Some of the numbers are | |
02:23 | greater than four and some are less . But if | |
02:25 | the amounts could all be made the same , they | |
02:27 | would all become for . So that's the concept of | |
02:30 | the mean . It's the value you'd get if you | |
02:32 | could smooth out or flatten all of the different data | |
02:35 | values into one consistent value . But is there a | |
02:39 | way that we could use math to calculate the mean | |
02:41 | of a dataset ? After all ? It would be | |
02:43 | very inconvenient if we always had to use stacks of | |
02:46 | blocks to do it . There's gotta be an easier | |
02:49 | way man . It's tough . Yeah . To learn | |
02:55 | the mathematical procedure for calculating the mean . Let's start | |
02:58 | with blocks again . But this time instead of using | |
03:00 | trial and error , let's use a more systematic way | |
03:02 | to make the stacks all the same height . This | |
03:05 | way involves a clever combination of addition and division . | |
03:09 | We know that we want to end up with five | |
03:10 | stacks that all have the same number of blocks . | |
03:12 | Right ? So first let's add up all of the | |
03:15 | numbers , which is like putting all of the blocks | |
03:17 | we have into one big stack , Adding up all | |
03:20 | of the numbers , or counting all the blocks shows | |
03:22 | us that we have a total of 20 . Next | |
03:25 | we divide that number or stack into five equal parts | |
03:28 | . Since the stack has a total of 20 blocks | |
03:31 | , dividing it into five equal stacks means that we'll | |
03:33 | have four in each since 20 divided by five equals | |
03:36 | four . So that's the math procedure you use to | |
03:39 | find the mean of a data set . It's just | |
03:41 | two simple steps . First , you add up all | |
03:44 | the numbers in the set and then you divide the | |
03:46 | total you get by how many numbers you add it | |
03:48 | up . The answer you get is the mean of | |
03:51 | the data set . Let's use that procedure to find | |
03:54 | the mean age of the members of this fine looking | |
03:56 | family here . If we add them all up using | |
03:58 | a calculator or by hand , if you'd like , | |
04:00 | the total of the ages is 222 years . But | |
04:04 | then we need to divide that total by the number | |
04:06 | of ages we added , which is six , 222 | |
04:09 | , divided by six is 37 . So that's the | |
04:12 | mean age of all the members in this family . | |
04:15 | All right . That's the mean . Now what about | |
04:18 | the median ? The median is the middle of a | |
04:20 | dataset ? It's the number that splits the data set | |
04:23 | into two equally sized groups or halves . One half | |
04:26 | contains members that are greater than or equal to the | |
04:28 | median and the other half contains members that are less | |
04:31 | than or equal to the median . Sometimes finding the | |
04:34 | median of a data set is easy and sometimes it's | |
04:36 | hard . That's because finding the middle value of a | |
04:39 | dataset requires that its members be an order from the | |
04:42 | least to the greatest or vice versa . And if | |
04:46 | the data set has a lot of numbers , it | |
04:47 | might take a lot of work to put them in | |
04:49 | the right order if they aren't already that way . | |
04:52 | So to make things easier , let's start with a | |
04:54 | really basic data set that isn't in order . It's | |
04:57 | pretty easy to see that we can put this data | |
04:59 | set in order from the least to the greatest value | |
05:01 | just by switching the two in the one there . | |
05:04 | Now we have the data set 123 And finding the | |
05:07 | median or middle of this data set is easy . | |
05:10 | It's just too because the two is located exactly in | |
05:13 | the middle . That almost seems too easy , doesn't | |
05:15 | it ? But don't worry , it gets harder . | |
05:17 | But before we try a harder problem , I want | |
05:19 | to point out that sometimes the mean and the median | |
05:22 | of a data set are the same number and sometimes | |
05:24 | they're not in the case of our simple data set | |
05:27 | 123 the meeting is to And the mean is also | |
05:30 | too . As you can see if we rearrange the | |
05:32 | amounts or follow the procedure , we learn to calculate | |
05:35 | the mean . But what about the first data set | |
05:37 | that we found ? The mean of ? We determined | |
05:39 | that the mean of this data set is for . | |
05:41 | But what about the median ? Well , the median | |
05:44 | is the middle . And since this data set is | |
05:47 | already in order from least to greatest , It's easy | |
05:49 | to see that the three is located in the middle | |
05:52 | since it splits the other members into two equal groups | |
05:55 | . So for this data set , the mean is | |
05:57 | four , but the median is three . So to | |
06:00 | find the median of a set of numbers first , | |
06:02 | you need to make sure that all the numbers are | |
06:04 | in order . And then you can identify the member | |
06:06 | that's exactly in the middle by making sure there's an | |
06:09 | equal number of members on either side of it . | |
06:11 | Okay . So far so good . But some of | |
06:14 | you may be wondering what if a dataset doesn't have | |
06:17 | an obvious middle member ? All of the sets we | |
06:19 | found the median of so far have an odd number | |
06:21 | of members . But what if a set has an | |
06:24 | even number of members like the data set ? 1234 | |
06:28 | There isn't a member in the middle that splits the | |
06:30 | set into two equally sized groups . If that's the | |
06:33 | case , we can actually use what we learned about | |
06:35 | the mean . To help us out . If the | |
06:37 | dataset has an even number of members , then to | |
06:40 | find the median , we need to take the middle | |
06:42 | two numbers and calculate the mean or average of those | |
06:45 | two . By doing that , we're basically figuring out | |
06:48 | what number would be exactly halfway between the two middle | |
06:51 | numbers and that number will be our medium . For | |
06:55 | example , in the set 1234 we need to take | |
06:58 | the middle two numbers two and three and find the | |
07:00 | mean of those numbers . We can do that by | |
07:03 | adding two and three and then dividing by two , | |
07:06 | two plus two equals five and five divided by two | |
07:08 | is 2.5 . So the median of the data set | |
07:11 | is 2.5 . Even though the number 2.5 isn't actually | |
07:16 | a member of the data set , it's the median | |
07:18 | because it represents the middle of the data set and | |
07:21 | it splits the members into two equally sized groups . | |
07:24 | Okay , so now , you know the difference between | |
07:26 | mean and median ? But what about the mode of | |
07:29 | a data set ? What in the world does that | |
07:31 | mean ? Well , mode is just a technical word | |
07:35 | for the value in a data set that occurs most | |
07:37 | often in the datasets . We've seen so far . | |
07:40 | There hasn't even been a mode because none of the | |
07:42 | data values were ever repeated . But what if you | |
07:45 | had this data set ? This set has six members | |
07:48 | , but some of the values are repeated . If | |
07:50 | we rearrange them , you can see that there's 112 | |
07:53 | twos and three threes . The mode of this data | |
07:56 | set is the value that occurs most often or most | |
07:59 | frequently . So that would be three . Since there's | |
08:02 | three threes Now don't get confused just because the # | |
08:05 | three was repeated three times . The mod is the | |
08:08 | number that's repeated most often ? Not how many times | |
08:11 | it was repeated as I mentioned . If each member | |
08:14 | in the dataset occurs only once . It has no | |
08:16 | mode . But it's also possible for a data set | |
08:18 | to have more than one mode . Here is an | |
08:20 | example of a data set like that . In this | |
08:23 | set , the number seven is repeated twice , but | |
08:25 | so is the number 15 . That means they tie | |
08:28 | for the title of mode . This set has two | |
08:30 | modes , seven and 15 . Okay , So now | |
08:34 | that you know what the mean , median and mode | |
08:36 | of a data set are let's put all that new | |
08:38 | information to use in one final real world example , | |
08:42 | suppose there's this guy who makes and sells custom electric | |
08:45 | guitars . Here is a table showing how many guitars | |
08:48 | he sold during each month of the year . Let's | |
08:51 | find the mean median and mode of this data set | |
08:54 | . First to find the mean . We need to | |
08:56 | add up the number of guitar sold in each month | |
08:59 | . You can do the addition by hand or you | |
09:00 | can use a calculator if you want to . Either | |
09:02 | way , be careful since that's a lot of numbers | |
09:05 | stand up and we don't want to make a mistake | |
09:07 | . The answer I get is 108 . So that's | |
09:10 | the total he sold for the whole year . But | |
09:12 | to get the mean sold each month , we need | |
09:14 | to divide that total by the number of months , | |
09:16 | which is 12 108 , divided by 12 is nine | |
09:20 | . So the mean or average is nine Next to | |
09:24 | find the median of the data set . We're going | |
09:25 | to have to rearrange the 12 data points in order | |
09:28 | from smallest to largest . So we can figure out | |
09:30 | what the middle value is there . That's better . | |
09:34 | Since there's an even number of members in this set | |
09:36 | , we can't just choose the middle number . So | |
09:38 | we're going to have to pick the Middle two numbers | |
09:40 | and then find the mean of them . nine and | |
09:42 | 10 are in the middle . Since there's an equal | |
09:44 | number of data values on either side of them . | |
09:46 | So we need to take the mean of nine and | |
09:48 | 10 . That's easy . Nine plus 10 equals 19 | |
09:52 | and then 19 divided by two is 9.5 . So | |
09:55 | the median number of guitar sold is 9.5 . That | |
09:59 | means that in half of the months he sold more | |
10:00 | than 9.5 and in half of the months he sold | |
10:03 | less than 9.5 . Last of all , let's identify | |
10:06 | the mode of this data set if there is one | |
10:09 | . Well , let's see there's two eights in the | |
10:11 | dataset . Oh , but there's 3/10 That looks like | |
10:15 | the most frequent number . So 10 is the mode | |
10:18 | of this data set . It's the result that occurred | |
10:20 | most often . All right . So that's the basics | |
10:23 | of mean median and mode . There are three really | |
10:27 | useful properties of datasets and now you know how to | |
10:29 | find them . But sometimes the hardest part about mean | |
10:33 | median and mode is just remembering which is which So | |
10:36 | remember that mean means average median is in the middle | |
10:41 | and mode starts with M . O . Which can | |
10:43 | remind you that it's the number that occurs most often | |
10:47 | . Remember to get good at Math . You need | |
10:49 | to do more than just watch videos about it . | |
10:51 | You need to practice so be sure to try finding | |
10:53 | the mean median and mode on your own . As | |
10:56 | always . Thanks for watching Math Antics and I'll see | |
10:58 | you next time . Learn more at Math Antics dot | |
11:02 | com |
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