Lumos StepUp High School Algebra 1 - Mathematics Practice test + Workbook Writing Expressions in Equivalent Forms

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Matthew was asked to solve $$64x^2+16-3=0$$ using the method of Complete the Square'' and his work is shown below. Did he solve it correctly, yes or no? Why?$$64x^2+16-3=0$$$$(8x+3)(8x-1)=0$$$$8x+3=0\ \ \ \ \ \ \ \ \ \ 8x-1=0$$$$8x=\ -3\ \ \ \ \ \ \ \ \ \ \ \ \ 8x=1$$$$x=\ \frac{-3}{8}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=\ \frac{1}{8}$$

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