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https://www.khanacademy.org/...theorem/...theorem/.../area-of-an-isosceles- triangle

Sal uses the Pythagorean **theorem** to find area of an isosceles triangle. ...

Practice: Use Pythagorean **theorem** to find **right triangle** side lengths ... [Tutor]

Pause this video and see if you can find the area of this triangle, and I'**ll** give you

two hints. ... same length, well that **means** that these are going to be **congruent**

triangles.

https://www.khanacademy.org/...theorem/.../pythagorean-theorem-with-right- triangle

If you're seeing this message, it **means** we're having trouble loading external

resources on our website. .... Intro to the Pythagorean **theorem 2** ... Practice: Use

Pythagorean **theorem** to find **right triangle** side lengths ... that is the same this

altitude of 12 is on both triangles, we know that both of these triangles are

**congruent**.

https://www.ets.org/s/gre/.../GRE_Math_Review_3_Geometry.doc

The material in the Math Review includes many **definitions**, properties, and

examples, as well as .... Type **2**: A triangle with at least two **congruent** sides is

called an isosceles triangle. ... Type **3: A** triangle with an interior right angle is

called a **right triangle**. ... By the Pythagorean **theorem** 8 squared = 5 squared, +, x

squared .

https://www.khanacademy.org/...theorem/.../angle-bisector-theorem-examples

Sal uses the angle bisector **theorem** to solve for sides of a **triangle**. ... If you're

seeing this message, it **means** we're having trouble loading external .... bisector,

because they're telling us that this angle is **congruent** to that angle **right** over

there. And then they tell us that the length of just this part of this side **right** over

here is **2**.

www.jmap.org/JMAPRegentsExamArchives/.../0116ExamGEOans.pdf

Parts **II**, **III**, and IV directly in this booklet. ... 1 William is drawing pictures of cross

sections of the **right** circular cone ... 8 **Triangle** ABC and **triangle DEF** are

graphed on the set of axes below. ... ABC, the complement of LB is **LA**. ....

decides to apply this **theorem** to the diagram: "An angle inscribed in ... A'B'C'

**congruent** to b.

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