Simplifying and Solving Equations Videos - Free Educational Videos for Students in K - 12

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This page provides a list of educational videos related to Simplifying and Solving Equations. You can also use this page to find sample questions, apps, worksheets, lessons , infographics and presentations related to Simplifying and Solving Equations.


Solve equations and simplify expressions


By MathPlanetVideos

Solve the given equation 12(3b−b4a)=36

One-step equations with multiplication and division


By Khan Academy

This equation can be simplified through a single step to solve for the variable. Can you help?

Solve equations with one rational expression (advanced)


By Khan Academy

Sal solves the following equation by first simplifying the rational expression: x^2-(x^2-4)/(x-2)=4.

One-step equations with multiplication and division


By Khan Academy

This equation can be simplified through a single step to solve for the variable. Can you help?

One-Step Addition Equations | MathHelp.com


By MathHelp.com

This lesson covers number patterns. Students learn to find the next 3 terms in advanced patterns that involve figures, letters, or numbers. For example, to find the next three terms in the pattern A, Z, B, Y, __, __, __, notice that the first and third terms in the pattern, A and B, are the first two letters in the alphabet, so the fifth and seventh terms in the pattern will be the next two letters in the alphabet, C and D. And the second and fourth terms in the pattern, Z and Y, are the last letter and the second-to-last letter in the alphabet, so the sixth term in the pattern will be the third-to-last letter in the alphabet, X. So the next three terms in the pattern A, Z, B, Y, __, __, __ are C, X, and D.

Quadratic Word Problems | MathHelp.com


By MathHelp.com

A number is 56 less than its square. Find the number. To solve this problem, let’s translate the first sentence into an equation. A number, that’s x, is, =, 56 less than it’s square, that’s x squared – 56. Remember that “less than” switches the order around. In other words, “56 less than its square” is not 56 minus x squared, it’s x squared minus 56. Next, since we have an x squared term in our equation, we set it equal to 0 by subtracting x from both sides, and we have 0 = x squared – x – 56. Next, we factor the right side as the product of two binomials. In the first position of each binomial, we have the factors of x squared, x and x. In the second position of each binomial, we’re looking for the factors of -56 that add to -1, which are -8 and positive 7. So we have 0 = x - 8 times x + 7, which means that either 0 = x – 8 or 0 = x + 7. Finally, in the first equation, we add 8 to both sides, to get 8 = x. And in the second equation, we subtract 7 from both sides, to get -7 = x. So 8 = x or -7 = x. It’s important to understand that both of these answers work. Plugging an 8 back into the original problem, we have 8 is 56 less than 8 squared, or 8 = 8 squared – 56, which simplifies to 8 = 64 – 56, or 8 = 8, which is a true statement. And plugging a -7 back into the original problem, we have -7 is 56 less than -7 squared, or -7 = -7 squared – 56, which simplifies to -7 = 49 – 56, or -7 = -7, which is also a true statement.

How to Do Algebra | MathHelp.com


By MathHelp.com

MathHelp.com offers comprehensive Algebra 2 help with a personal math teacher. Perfect for students who need lots of Algebra 2 help to get back up to speed in school, as well as homeschoolers looking for a complete Algebra 2 course.

Solve equations with two rational expressions


By Khan Academy

Sal solves the following equation and eliminates the resulting extraneous solution: (x^2)/(x+2)=4/(x+2).

Solve equations with two rational expressions


By Khan Academy

Sal solves the equation 5/(2x)-4/(3x)=7/18 by first finding the LCM (least common multiple) of 2x and 3x.

Solve equations with two rational expressions


By Khan Academy

Sal solves the equation 4/(p-1)=5/(p+3).

Solving Natural Logarithms | MathHelp.com


By MathHelp.com

In this example, we’re asked to expand the given logarithmic expression, log base 3 of M squared N to the 5th. Remember that our first law of logarithms states that if two values are multiplied together inside a logarithm, such as M squared times N to the 5th, then we can expand the logarithm into the sum of two separate logarithms, in this case log base 3 of M squared plus log base 3 of N to the 5th. Next, notice that each logarithm has a power inside the logarithm, and remember that our third law of logarithms states that if we have a power inside a logarithm, we can move the exponent to the front of the logarithm, so we have 2 times log base 3 of M + 5 times log base 3 of N.

Multi Step Equations | MathHelp.com


By MathHelp.com

This lesson covers complementary angles. Students learn the definition of complementary and supplementary angles, as well as how to find the measures of the complement and supplement of a given angle. Students are also asked to solve word problems in the following form: "If the ratio of an angle to its complement is 2:3, find the measure of each angle."